3n^2+21n+36=0

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Solution for 3n^2+21n+36=0 equation: 



3n^2+21n+36=0

a = 3; b = 21; c = +36;
Δ = b2-4ac
Δ = 212-4·3·36
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$


$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-3}{2*3}=\frac{-24}{6}
=-4
$


$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+3}{2*3}=\frac{-18}{6}
=-3
$

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